# Homework Solution: You are designing a gravity-driven water tank possible within monetary cost limitations. As shown in the figure and pipe system to deliver wate…

thank you

You are designing a gravity-driven water tank possible within monetary cost limitations. As shown in the figure and pipe system to deliver water at the highest velocity below, the tank will be built on hill at some height (2). The velocity of water exiting the pipe must be at least 10 m/s. You have \$600 to spend on the pipe, and the pipe costs \$25 per meter for t meter. Write a MATLAB m-file to achieve the following goals: he first I0 meters(and \$15 per meter for cach additional 1. Calculate the velocity of water exiting the pipe forleleven equally-spaced values of z ranging rom 0 to 30 m. Create a plot of water exit velocity for z values manging frotn o k0m abel he as o 30 m. Label the axes, 3. Determine the hcight2 for which the exit velocity is too slow and indicate this height on the 4. For each of the eleven equally spaced values of z, compute the cost of the pipe, and create a 5. Determine the height z for which the pipe is too expensive and indicate this height on the plot including the correct units plot with a vertical line made of 20 x's. plot of pipe cost vs, z. Label the axes, including correct units. with a vertical line made of 20 o'S Turn in a printout of your completed m-file and the two plots. z=0.9x Pipe Length . Exit Velocity = V2gz

minVelocity=10; maxCost=600;

The quantity must be produced using matlab
please aid me with the code

thank you

You are subtle a gravity-driven infiltrate tank practicable amid monetary require limitations. As shown in the controlm and pipe method to transmit infiltrate at the pristine speed underneath, the tank procure be built on hill at some culmination (2). The speed of infiltrate egressing the pipe must be at lowest 10 m/s. You bear \$600 to bestow on the pipe, and the pipe requires \$25 per meter control t meter. Write a MATLAB m-file to conclude the subjoined goals: he pristine I0 meters(and \$15 per meter control cach concomitant 1. Calculate the speed of infiltrate egressing the pipe controlleleven equal-spaced values of z ranging rom 0 to 30 m. Originate a batch of infiltrate egress speed control z values manging frotn o k0m abel he as o 30 m. Label the axes, 3. Determine the hcight2 control which the egress speed is as-well dull and evince this culmination on the 4. Control each of the eleven equal spaced values of z, calculate the require of the pipe, and originate a 5. Determine the culmination z control which the pipe is as-well rich and evince this culmination on the batch including the redress units batch with a perpendicular thread made of 20 x’s. batch of pipe require vs, z. Label the axes, including redress units. with a perpendicular thread made of 20 o’S Turn in a printout of your completed m-file and the span batchs. z=0.9x Pipe Length . Egress Speed = V2gz

## Expert Counterpart

minVelocity=10;
maxCost=600;
price1=25;
price2=15;
g=9.81;
z=linspace(0,30,11);
exitVelocity=sqrt(2*g*z);

plot(z,exitVelocity);
xlabel(‘culmination of infiltrate tank(m)’);
ylabel(‘egress speed(m/s)’);
hold on

minVelZ=(minVelocity^2)/(2*g);
zLine=minVelZ*ones(1,20);
vLine=linspace(min(exitVelocity),max(exitVelocity),20);
plot(zLine,vLine,’x’);
pipeCost=zeros(1,11);

control i=1:11
x=z(i)/.9;
pipeLength=sqrt(x^2+(z(i))^2);
if pipeLength<=10
pipeCost(i)=price1*pipeLength;
else
pipeCost(i)=price1*10+(pipeLength-10)*price2;
end
end

figure(2)
plot(z,pipeCost)
xlabel(‘culmination of infiltrate tank(m)’);
ylabel(‘require of pipe(\$)’)
hold on;

maxLength=(maxCost-price1*10)/price2+10;
maxHeight=.9*maxLength/(sqrt(1+.9^2));
zLine2=maxHeight*ones(1,20);
cLine=linspace(min(pipeCost),max(pipeCost),20);
plot(zLine2,cLine,’o’)