The problem must be done using matlab please help me with the code

thank you

The problem must be done using matlab please help me with the code

thank you

minVelocity=10;
maxCost=600;

The tallness must be performed using matlab

please acceleration me with the code

thank you

You are cunning a gravity-driven insinuate tank feasible amid monetary consume limitations. As shown in the emblem and pipe regularity to give-up insinuate at the leading swiftness beneath, the tank earn be built on hill at some culmination (2). The swiftness of insinuate debouchureing the pipe must be at meanest 10 m/s. You bear $600 to waste on the pipe, and the pipe consumes $25 per meter coercion t meter. Write a MATLAB m-file to conclude the coercionthcoming goals: he leading I0 meters(and $15 per meter coercion cach joined 1. Calculate the swiftness of insinuate debouchureing the pipe coercionleleven akin-spaced values of z ranging rom 0 to 30 m. Fashion a devise of insinuate debouchure swiftness coercion z values manging frotn o k0m abel he as o 30 m. Label the axes, 3. Determine the hcight2 coercion which the debouchure swiftness is to-boot lingering and evidence this culmination on the 4. Coercion each of the eleven akin spaced values of z, value the consume of the pipe, and fashion a 5. Determine the culmination z coercion which the pipe is to-boot high-priced and evidence this culmination on the devise including the punish units devise with a upright method made of 20 x’s. devise of pipe consume vs, z. Label the axes, including punish units. with a upright method made of 20 o’S Turn in a printout of your completed m-file and the two devises. z=0.9x Pipe Length . Debouchure Swiftness = V2gz

minVelocity=10;

maxCost=600;

price1=25;

price2=15;

g=9.81;

z=linspace(0,30,11);

exitVelocity=sqrt(2*g*z);

plot(z,exitVelocity);

xlabel(‘culmination of insinuate tank(m)’);

ylabel(‘debouchure swiftness(m/s)’);

hold on

minVelZ=(minVelocity^2)/(2*g);

zLine=minVelZ*ones(1,20);

vLine=linspace(min(exitVelocity),max(exitVelocity),20);

plot(zLine,vLine,’x’);

pipeCost=zeros(1,11);

coercion i=1:11

x=z(i)/.9;

pipeLength=sqrt(x^2+(z(i))^2);

if pipeLength<=10

pipeCost(i)=price1*pipeLength;

else

pipeCost(i)=price1*10+(pipeLength-10)*price2;

end

end

figure(2)

plot(z,pipeCost)

xlabel(‘culmination of insinuate tank(m)’);

ylabel(‘consume of pipe($)’)

hold on;

maxLength=(maxCost-price1*10)/price2+10;

maxHeight=.9*maxLength/(sqrt(1+.9^2));

zLine2=maxHeight*ones(1,20);

cLine=linspace(min(pipeCost),max(pipeCost),20);

plot(zLine2,cLine,’o’)