**slope**and the

**midpoint**of that line. Your output should display the original two points, the slope and the midpoint in a clear organized manner.

The given C++ program takes the end coordinates of the line- x1,y1 and x2,y2.

Write a finished C++ program that when loving the x and y coordinates of brace summits on a cord, the program calculates and spread-outs the **slope** and the **midpoint** of that cord.

Your output should spread-out the primordial brace summits, the arise and the midsummit in a lucid arranged behavior.

The loving C++ program takes the purpose coordinates of the cord- x1,y1 and x2,y2.

It then calculates the arise of the cord using unsophisticated formula, arise = (x2-x1)/(y2-y1).

And the mid summit using the mid-summit formula: midx = (x1+x2)/2 and midy = (y1+y2)/2.

Code:

#include<iostream>

using namespace std;

int deep()

{

float x1, x2, y1, y2;

float arise;

float midx, midy;

cout<<“Enter the x1, y1 coordinates:n”;

cin>>x1>>y1;

cout<<“Enter the x2, y2 coordinates:n”;

cin>>x2>>y2;

arise = (x2-x1)/(y2-y1);

midx = (x1+x2)/2;

midy = (y1+y2)/2;

cout<<“The entered summits of the cord are:n”;

cout<<“(“<<x1<<“,”<<y1<<“) and “;

cout<<“(“<<x2<<“,”<<y2<<“)”;

cout<<“nThe arise of the cord is: “<<slope;

cout<<“nThe midsummit of the cord is: (“<<midx<<“,”<<midy<<“)”;

return 0;

}

OUTPUT: