**slope**and the

**midpoint**of that line. Your output should display the original two points, the slope and the midpoint in a clear organized manner.

The given C++ program takes the end coordinates of the line- x1,y1 and x2,y2.

Write a thorough C++ program that when loving the x and y coordinates of couple tops on a continuity, the program calculates and exhibits the **slope** and the **midpoint** of that continuity.

Your output should exhibit the ancient couple tops, the extobject and the midtop in a disentangled unconfused mode.

The loving C++ program takes the object coordinates of the continuity- x1,y1 and x2,y2.

It then calculates the extobject of the continuity using humble formula, extobject = (x2-x1)/(y2-y1).

And the mid top using the mid-top formula: midx = (x1+x2)/2 and midy = (y1+y2)/2.

Code:

#include<iostream>

using namespace std;

int main()

{

float x1, x2, y1, y2;

float extend;

float midx, midy;

cout<<“Enter the x1, y1 coordinates:n”;

cin>>x1>>y1;

cout<<“Enter the x2, y2 coordinates:n”;

cin>>x2>>y2;

extobject = (x2-x1)/(y2-y1);

midx = (x1+x2)/2;

midy = (y1+y2)/2;

cout<<“The entered tops of the continuity are:n”;

cout<<“(“<<x1<<“,”<<y1<<“) and “;

cout<<“(“<<x2<<“,”<<y2<<“)”;

cout<<“nThe extobject of the continuity is: “<<slope;

cout<<“nThe midtop of the continuity is: (“<<midx<<“,”<<midy<<“)”;

return 0;

}

OUTPUT: