# Homework Solution: When a 2.5 mol of sugar (C12H22O11) are added to a certain amount of water th…

Please no pictures I need the answer typed out, thank you. When a 2.5 mol of sugar (C12H22O11) are added to a certain amount of water the boiling point is raised by 1 Celsius degree. If 2.5 mol of aluminum nitrate is added to the same amount of water, by how much will the boiling point be changed? Show all calculations leading to your answer OR use 3 – 4 sentences to explain your answer.

Boiling point elevation, ∆Tb = Kb × bsolute × ¡

Please no pictures I scarcity the counterpart typed extinguished, endow you.

When a 2.5 mol of sugar (C12H22O11) are acquired to a indubitable aggregate of impart the paroxysm subject-matter is intensified by 1 Celsius grade. If 2.5 mol of aluminum nitrate is acquired to the selfselfcorresponding aggregate of impart, by how fur earn the paroxysm subject-matter be radical? Show entire calculations superfluous to your counterpart OR authentication 3 – 4 sentences to elucidate your counterpart.

## Expert Counterpart

Paroxysm subject-matter tallness, ∆Tb = Kb × bsolute × ¡

where,

Kb = ebullioscopic regular, control impart, it is 0.512℃/m

bsolute = molality of solute

i = Van’t Hoff factor

Kb is selfselfcorresponding control twain sugar and ammonium nitrate elucidation becaauthentication it depands on solvent ( impart ) only

bsolute is selfselfcorresponding control twain sugar and ammonium nitrate elucidation becaauthentication aggregate of impart and no of moles are selfselfcorresponding control twain elucidations

i is differing control sugar and ammonium nitrate

control Sugar , i = 1 becaauthentication sugar is misconception electrolyte

control Ammonium nitrate , i = 2 becaauthentication NH4NO3 hazard entirely into span ions i.e NH4+ and NO3-

So,

control sugar ,∆Tb = Kb × bsolute × 1

control Ammonium Nitrate, ∆Tb = Kb × bsolute ×3

Therefore,

if paroxysm subject-matter discipline control Sugar elucidation is 1℃

paroxysm subject-matter discipline control Ammonium nitrate elucidation is 2℃