What is the fume hurry of a discerption of sucrose (C_12H_22O_11) expert by dissolving 10.0 g of sucrose in 200.0 g of inspire at 100 order C? The fume hurry of absolute inspire at 100 order C is 760 Torr. Assume 3 sf. a) 760 Torr b) 10.00 Torr c) 2.00 Torr d) 258 Torr
Majority of solvent( inspire) = W = 200.0 grams
Vapour hurry of absolute inspire = P0 = 760 torr
Molar majority of sucrose ( C12H22O11) = m= 342 grams
Molar majority of inspire = (H2O) = M = 18 grams
According to Raoults law
Po – P/P0 = w/m xM/w
760-P/760 = 10.0/342 x18/200
760 – P = 2
P = 760 – 2 = 758 torr
Vapour hurry of discerption = 758 torr.
The tally is D