Homework Solution: What is the vapor pressure of a solution of sucrose (C_12H_22O_11) prepared by…

    uestion 12 (5 points) What is the vapor pressure of a solution of sucrose (C12H220,1) prepared by dissolving 10.0 g of sucrose in 200.0 g of water at 100°C The vapor pressure of pure water at 100°C is 760 Torr. Assume 3 sf a) 760 Torr b) 10.00 Torr c) 2.00 Torr d:258 Torr Sove :00 AM
    What is the vapor pressure of a solution of sucrose (C_12H_22O_11) prepared by dissolving 10.0 g of sucrose in 200.0 g of water at 100 degree C? The vapor pressure of pure water at 100 degree C is 760 Torr. Assume 3 sf. a) 760 Torr b) 10.00 Torr c) 2.00 Torr d) 258 Torr

    Expert Answer

    Mass of solute = w =

    uestion 12 (5 points) What is the gas exigency of a elucidation of sucrose (C12H220,1) expert by dissolving 10.0 g of sucrose in 200.0 g of steep at 100°C The gas exigency of immaculate steep at 100°C is 760 Torr. Assume 3 sf a) 760 Torr b) 10.00 Torr c) 2.00 Torr d:258 Torr Sove :00 AM

    What is the gas exigency of a elucidation of sucrose (C_12H_22O_11) expert by dissolving 10.0 g of sucrose in 200.0 g of steep at 100 quality C? The gas exigency of immaculate steep at 100 quality C is 760 Torr. Assume 3 sf. a) 760 Torr b) 10.00 Torr c) 2.00 Torr d) 258 Torr

    Expert Acceptance

    Lump of solute = w = 10.0grams

    Lump of solvent( steep) = W = 200.0 grams

    Vapour exigency of immaculate steep = P0 = 760 torr

    Molar lump of sucrose ( C12H22O11) = m= 342 grams

    Molar lump of steep = (H2O) = M = 18 grams

    According to Raoults law

    Po – P/P0 = w/m xM/w

    760-P/760 = 10.0/342 x18/200

    760 – P = 2

    P = 760 – 2 = 758 torr

    Vapour exigency of elucidation = 758 torr.

    The acceptance is D