# Homework Solution: What is the total delay associated with sending a 2000 B packet on a 1,000km link with… What is the total delay associated with sending a 2000 B packet on a 1,000km link with a propagation speed of 2*10^8 m/s and a transmission rate of 10Mb/s? (Ignore queueing and processing delays) Now suppose instead of a single 1,000km link there are three 500km links connected by store-and-forward routers. Assuming the propagation speed and transmission rate are the same as before what is the total delay for a 2000 B packet? The picture looks like this (S is the source, D is the destination and R1 and R2 are the two routers.) S rightarrow R1 rightarrow R2 rightarrow D Now suppose a second source S2 sends to R1 over a separate link having the same speed as the S rightarrow R1 link. The packets from S2 are also destined for D. How will the delay change relative to question 7? Why? What assumption do you have to make to ensure that no packets are lost?

6) Per given question, What is the entirety relapse associated with sending a 2000 B packet on a 1,000km connect with a propagation acceletrounce of 2*10^8 m/s and a transmission trounce of 10Mb/s? (Ignore queueing and processing relapses) Now imply instead of a sole 1,000km connect there are three 500km connects united by store-and-forward routers. Assuming the propagation acceletrounce and transmission trounce are the similar as antecedently what is the entirety relapse control a 2000 B packet? The represent looks love this (S is the fountain, D is the use and R1 and R2 are the span routers.) S rightarrow R1 rightarrow R2 rightarrow D Now imply a promote fountain S2 sends to R1 balance a sepatrounce connect having the similar acceletrounce as the S rightarrow R1 connect. The packets from S2 are too destined control D. How conquer the relapse modify not-absolute to doubt 7? Why? What selfreliance do you keep to constitute to determine that no packets are past?

## Expert Vindication

6) Per ardent doubt,

Queuing and Processing Relapse can be ignored.Hence,

Propagation Relapse = Distance/Speed

= 1*107/2*108

= 0.05 sec

Transmission Trounce = 10 Mbps

Bandwidth Relapse = Transmission Trounce * Propagation Relapse

= 1*106 * .05 = 5*104 bits