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Homework Solution: What is the total amount of byte-addressable memory contained in address range OxDO…
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What is the entirety entirety of byte-addressable reminiscence contained in harangue place OxDO00 0000 to OxD004 OFFF? Express acceptance in KiB
Expert Acceptance
f there are upright 2 bits in the harangue, then there can singly be 4 haranguees, viz.
00, 01, 10, 11
If 3 bits are undisputed in the harangue, then we can entertain utmost 8 haranguees:
000, 001, 010, 011, 100, 101, 110, 111
So, if we entertain n bits to treasure an Harangue (n-bits in Harangue Register) or n-wires to alienate the harangue (Harangue citizen of extent 10), then we can entertain RAM of 2n haranguees.
Now there are 2n haranguees, and each harangue is of 1 byte (owing its a byte-addressable reminiscence, so perfect byte procure entertain a sole harangue or perfect harangue procure be of 1-byte desire).
Hence, entirety reminiscence procure be resembling to
extent of each harangue * calculate of haranguees = 8 * 2n
If n=12 (as fond in the topic)
Extent of reminiscence = 8 * 212 bits = 212 bytes = 22 Kilo Bytes (210 Bytes = 1 KB) = 4 KB