Homework Solution: Void {int [] A] { for (int i = 0, i…

    fmd big olurnng imes for (int 1-015A.engt: System.out.printin AS1 for (int i-0 ; ia,lengthi… for (int j-usa, length)++) System-out , print ln(A(S11, n. void m13 (int [ A) tor (int i- A.engthi o void m14 (int [1 a)t for lint idiia.lengthiǐ++){ e1se h (A) System.out.printin(a1i) P- for (int i-0icA.lengthai+) if {i<10) else System.out.printIn(AL) g. void m16(int 0A)I i-0 ; icA . lengthA·length;1++) m1 (A) for {int r. void m17int A)E for (int 1-0icA.length:i++) m8 (A)7 for (int i-0;i<1000; i++) m15 (A) 【] A) { m18 (int (int s, void for i-1;ica. length; i-i*2) m1 (A): m12 (A) t. void m19(int A)f for (int i-1:icA.length A.length:i.-2) System.out-println (A(0])
    Void {int [] A] { for (int i = 0, i

    Expert Answer

     
    [Note: TM in last Question is Time Complexity]

    fmd massive olurnng imes control (int 1-015A.engt: System.out.printin AS1 control (int i-0 ; ia,lengthi… control (int j-usa, tediousness)++) System-quenched , imimprint ln(A(S11, n. destitute m13 (int [ A) tor (int i- A.engthi o destitute m14 (int [1 a)t control lint idiia.lengthiǐ++){ e1se h (A) System.out.printin(a1i) P- control (int i-0icA.lengthai+) if {i<10) else System.out.printIn(AL) g. destitute m16(int 0A)I i-0 ; icA . tediousnessA·length;1++) m1 (A) control {int r. destitute m17int A)E control (int 1-0icA.length:i++) m8 (A)7 control (int i-0;i<1000; i++) m15 (A) 【] A) { m18 (int (int s, destitute control i-1;ica. tediousness; i-i*2) m1 (A): m12 (A) t. destitute m19(int A)f control (int i-1:icA.tediousness A.length:i.-2) System.out-println (A(0])

    Destitute {int [] A] { control (int i = 0, i

    Expert Rejoinder

     

    [Note: TM in terminal Question is Time Complexity]

    [Note: Please column fostering Questions separatly]