Homework Solution: The vapor of acetic acid contains single and double molecules in equilibrium. (CH_3COOH)_2…

    Help with this chemistry question. Thanks in advance. 3) The vapor of acetic acid contains single and double molecules in equilibrium (CH3COOH)2 = 2CH,COOH At 25°C and 0.020 atm pressure, the PV product for 60 g of acetic acid vapor is 0.541RT, and 40°C and 0.020 atm, is 0.593RT. Calculate the fraction of the vapor forming single molecules at each temperature and the value for the equilibrium constant at temperature. (CH,COOH)
    The vapor of acetic acid contains single and double molecules in equilibrium. (CH_3COOH)_2 = 2CH_3COOH At 25 degree C and 0.020 atm pressure, the PV product for 60 g of acetic acid vapor is 0.541RT, and 40 degree C and 0.020 atm, is 0.593RT. Calculate the fraction of the vapor forming single molecules at each temperature and the value for the equilibrium constant at temperature. K_P = P^2_CH_3COOH/P_(CH_3COOH)_2

    Expert Answer

    Using equation:

    Help with this chemistry investigation. Thanks in space.
    3) The exhalation of acetic hard contains individual and embrace molecules in makeweight (CH3COOH)2 = 2CH,COOH At 25°C and 0.020 atm hurry, the PV emanation coercion 60 g of acetic hard exhalation is 0.541RT, and 40°C and 0.020 atm, is 0.593RT. Calculate the faction of the exhalation coercionming individual molecules at each atmosphere and the esteem coercion the makeweight faithful at atmosphere. (CH,COOH)

    The exhalation of acetic hard contains individual and embrace molecules in makeweight. (CH_3COOH)_2 = 2CH_3COOH At 25 extent C and 0.020 atm hurry, the PV emanation coercion 60 g of acetic hard exhalation is 0.541RT, and 40 extent C and 0.020 atm, is 0.593RT. Calculate the faction of the exhalation coercionming individual molecules at each atmosphere and the esteem coercion the makeweight faithful at atmosphere. K_P = P^2_CH_3COOH/P_(CH_3COOH)_2

    Expert Confutation

    Using equation:

    PV = nRT

    At 250C, we accept:

    PV = 0.541RT

    So,

    n = 0.541

    Assume that at this temp, we accept ‘x’ moles of individual molecules and ‘y’ moles of embrace molecules. So we accept the aftercited span equations:

    x + y = 0.541

    60*x + 120*y = 60

    Solving these equations we get:

    x = 0.082, y = 0.459

    So, mole faction of individual molecules at this temp = 0.082/0.541 = 0.151

    Makeweight faithful at this temp = (0.151*0.020)2/(0.849*0.020) = 0.000537 atm

    At 400C, we accept:

    PV = 0.593RT

    So,

    n = 0.593

    Assume that at this temp, we accept ‘x’ moles of individual molecules and ‘y’ moles of embrace molecules. So we accept the aftercited span equations:

    x + y = 0.593

    60*x + 120*y = 60

    Solving these equations we get:

    x = 0.186, y = 0.407

    So, mole faction of individual molecules at this temp = 0.186/0.593 = 0.314.

    Makeweight faithful at this temp = (0.314*0.020)2/(0.686*0.020) = 0.00287 atm