Homework Solution: The data to the right were collected for the myosin-catalysed hydrolysis of ATP….

    The data to the right were collected for the myosin-catalysed hydrolysis of ATP. Use these data to determine the values of Vmax (the maximum rate of the enzyme) and Km (the Michaelis Menten constant). Answer the four parts (a - d) below. 7.5 12.5 20.0 43.5 62.5 67.0 95.0 119 155 166 a) If you were to plot this data to graphically determine Vmax and Km using a Lineweaver-Burk plot, what would you plot for the following data? If you would plot the original data, enter the original value in the corresponding blank. Remember to perform any necessary unit conversions ATP graph as graph as pmol LsNumber Number 12.5 → pmol1 95.0 → L s pmo Number Number 43.5 → L pmol 155 → L s pmol Scroll down for parts b-d. b) Calculate the slope using the data points from part (a). Then determine the y-intercept using the second
    The data to the right were collected for the myosin-catalysed hydrolysis of ATP. Use these data to determine the values of Vmax (the maximum rate of the enzyme) and Km (the Michaelis Menten constant). Answer the four parts (a - d) below. 7.5 12.5 20.0 43.5 62.5 67.0 95.0 119 155 166 a) If you were to plot this data to graphically determine Vmax and Km using a Lineweaver-Burk plot, what would you plot for the following data? If you would plot the original data, enter the original value in the corresponding blank. Remember to perform any necessary unit conversions ATP graph as graph as pmol LsNumber Number 12.5 → pmol1 95.0 → L s pmo Number Number 43.5 → L pmol 155 → L s pmol Scroll down for parts b-d. b) Calculate the slope using the data points from part (a). Then determine the y-intercept using the second

    Expert Answer

    Answer: Part 1.

    The facts to the proper were firm restraint the myosin-catalysed hydrolysis of ATP. Representation these facts to indicate the appraises of Vmax (the utmost reprimand of the enzyme) and Km (the Michaelis Menten continuous). Response the indelicate faculty (a - d) under. 7.5 12.5 20.0 43.5 62.5 67.0 95.0 119 155 166 a) If you were to frame this facts to graphically indicate Vmax and Km using a Lineweaver-Burk frame, what would you frame restraint the restraintthcoming facts? If you would frame the initiatory facts, penetadmonish the initiatory appraise in the corresponding bleak. Remember to fulfil any compulsory ace transmutations ATP graph as graph as pmol LsNumber Number 12.5 → pmol1 95.0 → L s pmo Number Number 43.5 → L pmol 155 → L s pmol Scroll down restraint faculty b-d. b) Calculate the swell using the facts points from bisect (a). Then indicate the y-intercept using the second

    The facts to the proper were firm restraint the myosin-catalysed hydrolysis of ATP. Representation these facts to indicate the appraises of Vmax (the utmost reprimand of the enzyme) and Km (the Michaelis Menten continuous). Response the indelicate faculty (a – d) under. 7.5 12.5 20.0 43.5 62.5 67.0 95.0 119 155 166 a) If you were to frame this facts to graphically indicate Vmax and Km using a Lineweaver-Burk frame, what would you frame restraint the restraintthcoming facts? If you would frame the initiatory facts, penetadmonish the initiatory appraise in the corresponding bleak. Remember to fulfil any compulsory ace transmutations ATP graph as graph as pmol LsNumber Number 12.5 → pmol1 95.0 → L s pmo Number Number 43.5 → L pmol 155 → L s pmol Scroll down restraint faculty b-d. b) Calculate the swell using the facts points from bisect (a). Then indicate the y-intercept using the second

    Expert Response

    Answer: Bisect 1. Instructions restraint frameting LB Frame:

    (The order here in restraint MS Word 2016) –

    1. Penetadmonish [S] and V appraises in abound equivocation in separeprimand rows.

    2. Genereprimand 1/ [S] and 1/V appraises in abound equivocation.

    3. Select 1/[S] and 1/V columns and click on “Insert” tab proper to ‘Home’ tab.

    4. Select ‘scatter frame’ -displayed as rare dots in the graph

    5. Select trendline liberty

    6. Add straight trendline and bridle the liberty restraint ‘trendline equation’.

    # Determination of Vmax and Km using LB Frame

    Lineweaver-Burk frame gives an equation in from of Y = m X + c

    where, y = 1/ V0,       x = 1/ [S],

    Intercept, c = 1/ Vmax           ,

    Slope, m = Km/ Vmax

    Trendline (straight retreat) equation restraint “No- inhibitor” from LB frame y = 0.0758x + 0.0047.

    #b. Swell, m = 0.0758 s

    y-intercept, c = 0.0047 L s pmol-1

    #c. Now, from Intercept, c = 1/ Vmax

    Or, 0.0047= 1/ Vmax

    Or, Vmax = 1/ 0.0047 = 212.77

    Hence, Vmax = 212.77 pmol L-1 s-1

    Now,

    Km = m x Vmax = 0.0758 x 212.77 = 16.13

    Thus, Km = 16.13 umol L-1

    Note: There is no insufficiency of ace transmutation betwixt umol and pmol. Just representation the appertaining aces of Vo and [S] restraint fitted appraises of Vmax and Km.