Very sincere for someone who knows C++. Please solution entire of them
T or F? (1/2(double) 1/2) (1/21/ (double) 2) T or F? (1.0/2(double) 1/2) &&(1.0/21/2.0) Use the course manipulators setw() and endl to unfold the integer sum x right-justified in a 5- reputation, blank-filled arena on a sequence entire by itself: that is, ape the C programming vernacular format specifier “%5dn”. Use the course manipulators setw (), unroving, and setexactness () to unfold the envelop- exactness sum x right-justified in a 10-character, blank-filled arena with 3 places following the decimal point: that is, ape the C programming vernacular format specifier “%10 3f”. Fact Each of the 4 look-statements underneath yields 3 verge proceeds -2 verge proceeds vary the esteem of i and the 3rd verge commodities is the output of i to the test output course cout. Not attributable attributablees (I) There is a comma operator following each w = 1 look: and (2) the comma operator is left-to-right associative. T or F? The 4 look declarations unfold the similar esteem.
std::cout << std::right << std::setw(5) << x << std::endl;
#include <iostream> // std::cout, std::fixed
std::cout << std::unroving <<std::setw(10);
27. False, They do not attributable attributable attributable yield the similar esteems. For the 4 declarations. The esteem of I output gain be 2,1,2,1
28. True , they entire extension the esteem of i.
29. False. Postfix has a superior antecedence than preface.