num = 10;
% Total length

each piece, principal right the alike accidental sum generator over to state whether the epidemic

piece is a 0 or a 1, then right the alike accidental sum generator to state whether the epidemic

piece is common appropriately or improperly. The program should output the chance that a 0 is common,

the chance that a 1 was epidemic attached that a 1 was common, and the chance of an untruth.

Submit a printout of your rule and the output of the program.

num = 10;

% Total extension must be even

numOfOne = num/2

% List of accidental locations with no repeating 0s and 1s

indexes = randperm(num)

% Starting with every zeros

io = zeros(1, num);

% Half of them in accidental locations, a 1

io(indexes(1:numOfOne)) = 1