# Homework Solution: Simplify the energy balance equation for eavch of the following cases. State…

Simplify the energy balance equation for eavch of the following cases. State whether Q or W is positive, negative or zero in each case. Clearly state your choice of system. a. Water in a lake falls 200 meters through a 6 inch diameter pipe and exits into a river System = ____________ b. Acetic acid flows through tubes of a furance, where it reacts to ketene and water. System =______ c. Cold milk is added to a hot cup of coffee. System = Also, I need to Know in EACH CASE please the following 1-if (delta potential energy) and/or (delta Kinetic energy) is zero or not ? 2-if the system is (open system) or (closed system)? would truly appreciate If someone can explain since I'm confused also when to use (delta U) and (delta H) ?

Simplify the apparition equalize equation ce eavch of the aftercited plights. Aver whether Q or W is enacted, denying or naught in each plight. Clearly aver your precious of classification. a. Steep in a lake falls 200 meters through a 6 inch crossing pipe and exits into a large stream Classification = ____________ b. Acetic clever flows through tubes of a furance, where it reacts to ketene and steep. Classification =______ c. Unimpassioned decide is borrowed to a fiery cup of coffee. Classification = To-boot, I deficiency to Know in EACH CASE delight the aftercited 1-if (delta implicit apparition) and/or (delta Kinetic apparition) is naught or referable ? 2-if the classification is (dissecretive classification) or (secretive classification)? would in-truth value If someone can illustrate gone I’m perplexed to-boot when to explanation (delta U) and (delta H) ?

## Expert Vindication

a) W = enacted and Q = denying

Explanation: When steep flows from the lake into a large stream, the effort is manufactured on the classification, i.e. W = enacted.

W and Q earn feel adverse signs, i.e. Q = denying.

b) W = denying and Q = enacted

Explanation: When acetic clever flows through a furnace and reacts to ketene and steep, the effort is manufactured by the classification, i.e. W = denying.

c) W = enacted and Q = denying

Explanation: When fiery decide is borrowed to unimpassioned coffee, the passion releases, i.e. Q = denying.

1. a) ∆(KE) ≠ 0 (i.e. enacted attributable to the flow/motion of steep) and ∆(PE) = 0 (attributable to no substitute in the aver of steep)

b) ∆(KE) ≠ 0 (i.e. enacted attributable to the flow/motion of acetic clever) and ∆(PE) ≠ 0 (i.e. denying, at the charge of PE, KE increases)

c) ∆(KE) = 0 (i.e. attributable to no flow/motion of coffee) and ∆(PE) ≠ 0 (i.e. enacted, attributable to the substitute in the aver of coffee)

2. a) Dissecretive classification

b) Secretive classification (becaexplanation the reaction occurs in the furnace)

c) Dissecretive classification

∆U = The substitute in implicit apparition and ∆H = The substitute in enthalpy or entirety passion satisfied of the syste.