5) Tf = Kf x m

5) Tf = Kf x m

Tf = 5.48 – 5.08 = 0.4

m = Tf / Kf = 0.4 / 5.12 = 0.078

molality = (W/MW) (1000 / bulk of solvent in g)

0.078 = (2.0 / MW) (1000 / 100)

2.0 / MW = 0.0078

**MW = 256.41 g /mol**

* 6)* = iCRT

= osmotic influence = ?

i = 5 (Al2(SO4)3 gives 5 ions)

C = 0.01 M

R = 0.0821

T = 298 K

= 5 x 0.01 x 0.0821 x 298

** = 1.22 atm**