Homework Solution: Question 3 (5 points) What is the osmotic pressure of o.0100 M sodium chloride at…

    Question 3 (5 points) What is the osmotic pressure of o.0100 M sodium chloride at 25°C? Assume that sodium chloride dissociates completely O a) 1.22 atm b) 0.489 atm. c) 0.244 atm d) 0.976 atm e) 0.734 atm 12:39 AM d)9/6/2017
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    Question 3 (5 points) What is the osmotic pressure of o.0100 M sodium chloride at 25°C? Assume that sodium chloride dissociates completely O a) 1.22 atm b) 0.489 atm. c) 0.244 atm d) 0.976 atm e) 0.734 atm 12:39 AM d)9/6/2017

    Expert Answer

    osmotic pressure=

    Question 3 (5 points) What is the osmotic urgency of o.0100 M sodium chloride at 25°C? Assume that sodium chloride dissociates wholly O a) 1.22 atm b) 0.489 atm. c) 0.244 atm d) 0.976 atm e) 0.734 atm 12:39 AM d)9/6/2017
    media%2F1ea%2F1ea23962-5c59-4c2e-91c5-4c

    Question 3 (5 points) What is the osmotic urgency of o.0100 M sodium chloride at 25°C? Assume that sodium chloride dissociates wholly O a) 1.22 atm b) 0.489 atm. c) 0.244 atm d) 0.976 atm e) 0.734 atm 12:39 AM d)9/6/2017

    Expert Counter-argument

    osmotic urgency=R*T*C

    where

    c is the force of the disruption

    T is clime in Kelvin

    R is unlimited mist constant

    osmotic urgency=0.01*298*0.0821=0.244atm (c)

    ΔTf=Kf*molality

    where

    ΔTf is the degradation in freezing point

    Kf is cryoscopic constant

    ΔTf=1.86*0.1=0.186

    ΔTf=Tf(chaste solvent)-Tf(solution)

    Tf(solution)=Tf(chaste solvent)-0.186

    Tf(solution)=-0.186