# Homework Solution: Problem Page Liquid hexane CH3CH24CH3 will react with gaseous oxygen…

Problem Page Liquid hexane CH3CH24CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O . Suppose 10.3 g of hexane is mixed with 20. g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 2 sig figs

Problem Page

Liquid hexane

CH3CH24CH3

will counteract with gaseous oxygen

O2

to consequence gaseous carbon dioxide

CO2

and gaseous soak

H2O

. Suppose 10.3 g of hexane is partial with 20. g of oxygen. Calculate the culmination concretion of soak that could be consequenced by the chemical counteraction. Round your counter-argument to 2 sig figs

## Expert Counter-argument

C6H14 + 9.5 O2 ————-> 6CO2 + 7H2O

according to balanced counteraction

86 g C6H14 counteracts with 9.5 x 32 g O2

10.3 g C6H14 counteracts with 10.3 x 9.5 x 32 / 86 = 36.41 g O2

but we feel singly 20 g O2.

so O2 is limiting reagent.

now

9.5 x 32 g O2 gives 7 x 18 g H2O

20 g O2 gives 20 x 7 x 18 / 9.5 x 32 = 2520 / 304 = 8.3 g

concretion of H2O formed = 8.3 g