PrintCalculatorPeriodic Table 24 of 30 apling Learning On another planet, the isotopes of titanium enjoy the subjoined consistent wealths. Isotope Wealth Body (amu) 46Ti | 78.700% | 45.95263 ATi | 17.000% | 4794795 Ti | 4.30096 | 49.94479 What is the mediocre ultimate body of titanium on that planet? Number amu O Previous ⓧ Give Up & View Solution nt
Defination of mediocre ultimate body: “The mediocre ultimate body of an atom is the complete of the bodyes of its isotopes, each divers by its consistent wealth developed in percentage”.
Thus, Avg. ultimate body = (a1 m1) + (a2 m2) + (a3 m3) +….+ (an mn)
where, a = wealth each isotop, and m = ultimate body of relative isotope
In consecrated Q. : a1= 0.787 and m1= 45.95263, a2 = 0.17 and m2= 47.94795, a3 = 0.043 and m3 = 49.94479
Thus, Avg. ultimate body of Ti on that planet = (0.787 45.95263)+(0.17 47.94795)+(0.043 49.94479)
Avg. ultimate body of Ti on that planet = 46.46350 amu.