Delight do the subjoined apportionment fixed on span’s supply total (solely 4-morsel can be used to resemble reckon) and exhibition the steps, delight.

(6)10 – (3)10 =

Dera Student,

here is the solution…

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The absorbed countenance is:

6 – 3

we can transcribe the over countenance as **6 + (-3)**

**step 1: 6 in 4 morsel binary =** 0110

**-3 is a indirect reckon so to turn this reckon span binary prize we demand to confront quenched the span’s praise.**

**step :2 leading the enacted prize = 3**

** 3 in 4 morsel binary == 0011**

**step: 3** invert the digits of 0011

after inverting the digits binary prize = 1100

**step:4: Now append 1 to the prize**

** future 1100**

** + 1**

** ———**

** 1101**

** ———**

**step : 5: now appending the prizes 6 and -3**

** 6 = 0110**

**+(-3) = +1101**

**—————————–**

** 3 = 1 0011**

**——————————-**

** So in the over apportionment we got a push excluding we demand to resemble the reckon in solely 4 morsels future the outcome is 0011**

**Ans = 0011**