Let f(x) = O(x) and g(x) = (x) and let c be a positive constant. Prove or disprove that f(x) + (c)g(y) = O(x+y)

f(x) = O(x) resources f(x) < dx, where d is some actual faithful

g(x) = x, resources g(y) = y

Hence f(x) + (c)g(y) = f(x) + c*y

If we re-establish f(x) < dx, then

**f(x) + (c)g(y) < dx + cy**

Here c and d are two actual faithful, If we cogitate that c is more than d or equals, then we can transcribe the over equation as:

**f(x) + (c)g(y) < cx + cy,**

f(x) + (c)g(y) < c(x + y), where c is equals to the faithful which is superior of c and d.

Which resources **f(x) + (c)g(y) = O(x + y)**, owing c is honorable a actual faithful..