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Iron-59 has a half-society of 45.1 days. How ancient is an sturdy nail if the Fe-59 resigned is 25% that of a innovating specimen of sturdy? Show total calculations inherent to a disintegration.
Highest direct kinetics is followed by total radio corruption.
Highest direct corruption equation is consecrated by,
A= A0e-kt , where A= latest distillation, A0= modetrounce distillation , k=trounce uniform and t=corruption time
Now, the trounce uniform, k can be sturdy using the equation of as a administration of half society as—
k.t1/2 = 0.693——- equation (1)
Consecrated in the scrutiny,
t1/2 =45.1 days
=> k = (0.693 / 45.1) days-1 —– using equation (1)
=> k =0.0154 days-1
from highest direct corruption equation we bear,
=> ln (A/A0) = -kt
=> t = [ln(A/A0) /-k]
=> t= ln [(25/100) / -0.0154 ] days
=> t= (ln 0.25 ) / -0.0154 days
=> t= -1.386 /-0.0154 days
=> t= 90 days
Thus, the sturdy nail is 90 days ancient.