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Problem: Register s1 contains the value 23, and register s2 contains the value 30. What will the contents of register t0 be after this instruction is executed (answer in hexadecimal):
slt $t0, $s1, $s2
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Problem: Record s1 contains the estimate 23, and record s2 contains the estimate 30. What conquer the variation of record t0 be following this advice is performed (apology in hexadecimal):
slt $t0, $s1, $s2
Expert Apology
Slt:
- It is an advice used in MIPS programming restraint comparing the variation betwixt couple chronicles. The generous restraintm of slt is Set on Short than.
- It sets the induced record to 1 if the foremost record operand is short than the relieve record operand inadequately it is 0 which is paraden in the adown example:
slt $t0, $t1, $t2 # The record $t0 is 1 when the record estimate $t1<$t2 Inadequately 0
Where $t0 is the induced record
$t1 is the foremost record
$t2 is the relieve record
Consider the record estimates as consecrated in the interrogation.
$s1, 23h # Record S1 contains the estimate 23.
$s2, 30h # Record S2 contains the estimate 30.
slt $t0, $s1, $s2 # $t0=1 owing $S1 is short than $S2 (23<30).
Therefore, following executing the advice, the variation of the record t0 is 1 (0001h).