Homework Solution: For 3, please provide a good explanation…

    For 3, please provide a good explanation
    For4, please write a function file for the algorithm and use the function in a script file to solve the problem with comments 3. The equation ln(x) =-3x + 5. has a solution near z = 1.53, when setting up the problem as r - g(x) to be solved by a fixed point method, there are several options to choose the function g. For example, consider the functions gi (z) = (5 ln(z)/3 and g2(z) = e-3r+5 Justify your answer. . For which of these functions the fixed point method will converge? 1. Use MATLAB to find the fixed point of the previous problem using both functions gi (x) and g2(r). Use a tolerance of 109. Plot the sequence of points on corresponging to each function. You can do that using the following code g1 = 0(x) .. .. g2 = @(x) ,.. ; x0-1; tol = 10^ (-9) ; c1 = zeros (1,20); c2 = zeros (1,20); for max1-1:20 c1(max 1) c2 (maxi) = fixedpoint (gi,x0,tol,max1); fixedpoint (g2,xo,tol,max1): end figure (1); plot(c1) figure (2); plot (c2) You will notice that one converges and the other one does not. This should be con- sistent with your answer in the previous problem. Turn in the code, the value of the fixed point printed with at least 9 significant digits, and the plots that show the behavior of the sequences of points.
    3. The equation ln(x) =-3x + 5. has a solution near z = 1.53, when setting up the problem as r - g(x) to be solved by a fixed point method, there are several options to choose the function g. For example, consider the functions gi (z) = (5 ln(z)/3 and g2(z) = e-3r+5 Justify your answer. . For which of these functions the fixed point method will converge? 1. Use MATLAB to find the fixed point of the previous problem using both functions gi (x) and g2(r). Use a tolerance of 109. Plot the sequence of points on corresponging to each function. You can do that using the following code g1 = 0(x) .. .. g2 = @(x) ,.. ; x0-1; tol = 10^ (-9) ; c1 = zeros (1,20); c2 = zeros (1,20); for max1-1:20 c1(max 1) c2 (maxi) = fixedpoint (gi,x0,tol,max1); fixedpoint (g2,xo,tol,max1): end figure (1); plot(c1) figure (2); plot (c2) You will notice that one converges and the other one does not. This should be con- sistent with your answer in the previous problem. Turn in the code, the value of the fixed point printed with at least 9 significant digits, and the plots that show the behavior of the sequences of points.

    Expert Answer

    Coercion 3, delight cater a good-tempered-tempered explanation
    For4, delight transcribe a part refine coercion the algorithm and truth the part in a script refine to reresolve the tenor with comments
    3. The equation ln(x) =-3x + 5. has a breach adjacent z = 1.53, when elucidation up the tenor as r - g(x) to be resolved by a agricultural object process, there are distinct options to cull the part g. Coercion pattern, weigh the parts gi (z) = (5 ln(z)/3 and g2(z) = e-3r+5 Justify your repartee. . Coercion which of these parts the agricultural object process get meet? 1. Truth MATLAB to perceive the agricultural object of the anterior tenor using twain parts gi (x) and g2(r). Truth a tolerance of 109. Batch the progression of objects on corresponging to each part. You can do that using the subjoined principle g1 = 0(x) .. .. g2 = @(x) ,.. ; x0-1; tol = 10^ (-9) ; c1 = zeros (1,20); c2 = zeros (1,20); coercion max1-1:20 c1(max 1) c2 (maxi) = agriculturalobject (gi,x0,tol,max1); agriculturalobject (g2,xo,tol,max1): purpose illustration (1); batch(c1) illustration (2); batch (c2) You get mark that undivided meets and the other undivided does referable attributable attributable. This should be con- sistent with your repartee in the anterior tenor. Turn in the principle, the estimate of the agricultural object printed with at lowest 9 momentous digits, and the batchs that likeness the demeanor of the progressions of objects.

    3. The equation ln(x) =-3x + 5. has a breach adjacent z = 1.53, when elucidation up the tenor as r – g(x) to be resolved by a agricultural object process, there are distinct options to cull the part g. Coercion pattern, weigh the parts gi (z) = (5 ln(z)/3 and g2(z) = e-3r+5 Justify your repartee. . Coercion which of these parts the agricultural object process get meet? 1. Truth MATLAB to perceive the agricultural object of the anterior tenor using twain parts gi (x) and g2(r). Truth a tolerance of 109. Batch the progression of objects on corresponging to each part. You can do that using the subjoined principle g1 = 0(x) .. .. g2 = @(x) ,.. ; x0-1; tol = 10^ (-9) ; c1 = zeros (1,20); c2 = zeros (1,20); coercion max1-1:20 c1(max 1) c2 (maxi) = agriculturalobject (gi,x0,tol,max1); agriculturalobject (g2,xo,tol,max1): purpose illustration (1); batch(c1) illustration (2); batch (c2) You get mark that undivided meets and the other undivided does referable attributable attributable. This should be con- sistent with your repartee in the anterior tenor. Turn in the principle, the estimate of the agricultural object printed with at lowest 9 momentous digits, and the batchs that likeness the demeanor of the progressions of objects.

    Expert Repartee