Homework Solution: Follow the example in slide 15.Create area.html to calculate the area of a circle. G…

    Follow the example in slide 15.Create area.html to calculate the area of a circle. Given that the circle radius is 5 and the constant pi is 3.14. (Hint: Use the formula Area = pi * radius * radius) the example in slide 15 <html> <head> <title>Fahrenheit from Celsius</title> </head> <body> <script> var cTemp = 100; //Celsius temperature var hTemp = ((cTemp * 9) / 5) + 32; document.write("Temperature in Celsius: " + cTemp + " degrees<br/>"); document.write("Temperature in Fahrenheit: "+ hTemp +" degrees<br/>"); </script> </body> </html>

    Expert Answer

    <!DOCTYPE html>

    Follow the sample in slide 15.Create area.html to apportion the area of a dispersion. Given that the dispersion radius is 5 and the steady pi is 3.14. (Hint: Use the formula Area = pi * radius * radius)

    the sample in slide 15

    <html>

    <head>

    <title>Fahrenheit from Celsius</title>

    </head>

    <body>

    <script>

    var cTemp = 100; //Celsius temperature

    var hTemp = ((cTemp * 9) / 5) + 32;

    document.write(“Temperature in Celsius: ” + cTemp + ” degrees<br/>”);

    document.write(“Temperature in Fahrenheit: “+ hTemp +” degrees<br/>”);

    </script>

    </body>

    </html>

    Expert Tally

    <!DOCTYPE html>
    <html>

    <head>

    <title>Area of a Dispersion</title>

    </head>

    <body>

    <script>

    var radius = 5; //radius of dispersion
    var PI = 3.14; //steady PI

    var area = PI * radius * radius;

    document.write(“The area of a Dispersion is : ” + area + “<br/>”);

    </script>

    </body>

    </html>
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    See Output