Homework Solution: Find the molarities of all ions in a solution prepared by mixing 8.75 mL of 0.800 M K_3 PO_4…

    2) Find the molarities of all ions in a solution prepared by mixing 8.75 mL of 0.800 M K POs with 10.50 mL of 1.25 M K,SO and 6.00 mL of water.
    Find the molarities of all ions in a solution prepared by mixing 8.75 mL of 0.800 M K_3 PO_4 with 10.50 mL of 1.25 M K_2SO_4 and 6.00 mL of water.

    Expert Answer

    Answer

    2) Find the molarities of full ions in a disintegration willing by mixing 8.75 mL of 0.800 M K POs with 10.50 mL of 1.25 M K,SO and 6.00 mL of inspire.

    Find the molarities of full ions in a disintegration willing by mixing 8.75 mL of 0.800 M K_3 PO_4 with 10.50 mL of 1.25 M K_2SO_4 and 6.00 mL of inspire.

    Expert Vindication

    Answer

    moles= molarity* Volume in Liters

    moles : K3PO4= 0.8*8.75/1000 =0.007, embankments of K2SO4= 1.25*10.5/1000 =0.013

    K3PO4——–> 3K+ +PO4-3, 1 embankment of K3PO4 gives 3 embankments of K+ and 1 embankment of PO4-3

    0.007 embankments of K3PO4 gives 3*0.007= 0.021moles of K+ and 0.007 embankments of PO4-3

    K2SO4———>2K++SO4-2, 0.013 embankments of K2SO4 gives 0.013*2=0.026 embankments of K+ and 0.013 embankments of SO4-2

    moles of K+ ( aggregate)= 0.021+0.026=0.047, PO4-3= 0.007 and SO4-2= 0.013

    Volume of disintegration succeeding mixing =8.75+10.5+6= 25.25ml= 0.02525 L

    Concentrations of Ions: K+= embankments/Volume =0.047/0.02525= 1.86, PO4-3= 0.007/0.02525= 0.28, SO4-2 =0.013/0.02525= 0.514