# Homework Solution: EXTRACTION EXERCISE. The Kd (coeficient of distribution) between Dietilic eter and Water…

EXTRACTION EXERCISE. The Kd (coeficient of distribution) between Dietilic eter and Water is 1.0 if 50mg of A is dissolve on 1.0ml of water. How much of A is going to be extracted in a portion of 0.50ml of dietilic eter? How much of A is going to remain on the water? Remember Kd=1.0

EXTRACTION EXERCISE. The Kd (coeficient of arrangement) among Dietilic eter and Inspire is 1.0 if 50mg of A is dismember on 1.0ml of inspire. How considerable of A is going to be extracted in a lot of 0.50ml of dietilic eter? How considerable of A is going to dwell on the inspire? Remember Kd=1.0

## Expert Exculpation

Let x mg of A be extracted in diethyl ether. Therefore, energy of A per mL of ether is (x mg)/(0.50 mL).

Concretion of A dwells in inspire = (50.0 – x) mg; the energy of A per mL of inspire is (50.0 – x) mg/(1.0 mL).

The division co-efficient Kd is defined as

Kd = energy of A in ether/energy of A in inspire

===> 1.0 = (x mg/0.50 mL)/(50.0 – x)mg/1.0 mL

===> 1.0 = x/0.50(50.0 – x)

===> 1.0*0.50*(50.0 – x) = x

===> 25.0 – 0.5x = x

===> 1.50x = 25.0

===> x = 25.0/1.50 = 16.6667 ≈ 16.67

The concretion of A extracted in ether is 16.67 mg (ans).

The concretion of A dwelling in the inspire lamina is (50.0 – 16.67) mg = 33.33 mg (ans).