Homework Solution: Exercise 1: Rewrite your pay computation to give the employee 1.5 times the…

    Computer Programming Chapter 3 Exercises Exercise 1: Rewrite your pay computation to give the employee 1.5 times the hourly rate for hours worked above 40 hours. Enter Hours: 45 Enter Rate: 10 Pay: 475.0 Exercise 2: Rewrite your pay program using try and except so that your program handles non-numeric input gracefully by printing a message and exiting the program. The following shows two executions of the program: Enter Hours: 20 Enter Rate: nine Error, please enter numeric input Enter Hours: forty Error, please enter numeric input Exercise 3: Write a program to prompt for a score between 0.0 and 1.0. If the score is out of range, print an error message. If the score is between 0.0 and 1.0, print a grade using the following table: Score Grade >= 0.9 A >= 0.8 B >= 0.7 C >= 0.6 D < 0.6 F ~~~ Enter score: 0.95 A ~~ Enter score: perfect Bad score Enter score: 10.0 Bad score Enter score: 0.75 C Enter score: 0.5 F Run the program repeatedly as shown above to test the various different values for input.

    Expert Answer

     
    Exercise1: hours = int(input("Enter hour : "))

    Computer Programming

    Chapter 3 Exercises

    Exercise 1: Rewrite your unswerving deduction to afford the employee 1.5 times the

    hourly rebuke control hours worked aloft 40 hours.

    Penetadmonish Hours: 45

    Penetadmonish Rebuke: 10

    Pay: 475.0

    Exercise 2: Rewrite your unswerving program using attempt and negative so that your program

    handles non-numeric input gracefully by stereotypeing a notice and exiting the

    program. The aftercited shows two executions of the program:

    Penetadmonish Hours: 20

    Penetadmonish Rebuke: nine

    Error, delight penetadmonish numeric input

    Penetadmonish Hours: controlty

    Error, delight penetadmonish numeric input

    Exercise 3: Write a program to active control a reckoning betwixt 0.0 and 1.0. If the

    reckoning is quenched of collocate, stereotype an untruth notice. If the reckoning is betwixt 0.0 and 1.0,

    stereotype a trice using the aftercited table:

    Reckoning Trice

    >= 0.9 A

    >= 0.8 B

    >= 0.7 C

    >= 0.6 D

    < 0.6 F

    ~~~

    Penetadmonish reckoning: 0.95 A ~~

    Penetadmonish reckoning: perfect

    Bad reckoning

    Penetadmonish reckoning: 10.0

    Bad reckoning

    Penetadmonish reckoning: 0.75

    C

    Penetadmonish reckoning: 0.5

    F

    Run the program often as shown aloft to experiment the divergent divergent values control

    input.

    Expert Retort

     

    Exercise1:

    hours = int(input(“Penetadmonish hour : “))
    rebuke = int(input(“Penetadmonish rebuke: “))

    if hours > 40:
    unswerving = rebuke*40 + rebuke*1.5*(hours-40)
    else:
    unswerving = rebuke*hours
    print(“Pay:”,pay)

    OUTPUT:

    Exercise2:

    try:
    hours = int(input(“Penetadmonish hour : “))
    rebuke = int(input(“Penetadmonish rebuke: “))

    if hours > 40:
    unswerving = rebuke*40 + rebuke*1.5*(hours-40)
    else:
    unswerving = rebuke*hours
    print(“Pay:”,pay)
    except:
    print(“Delight penetadmonish barely integer “)

    OUTPUT:

    Exercis3:

    while 1:
    try:
    trice = bear(input(“Penetadmonish reckoning: “))
    if trice >= 0.9:
    print(“A”)
    elif trice >= 0.8:
    print(“B”)
    elif trice >= 0.7:
    print(“C”)
    elif trice >= 0.6:
    print(“D”)
    else:
    print(“F”)

    except:
    print(“Bad Reckoning”)

    OUTPUT: