Homework Solution: d ⓘ file:///Users/K-Hype/Downloads/C++Book-Ch7-Pointers-201 6%20(1).pdf Microsoft W…

    Consider the statements short n1=12, n2 = 3, *s1, *s2, *s3; s1 = &n1; If the following C++ statements below are executed along with the ones above as part of complete programs, show exactly what the memory will look like using the image above. You may show the numbers in decimal form rather than in binary form. (a) s2 = &n2; *(s2 - 1) = 19; (b) s3 = s1 + 12; *s3 = *s1 + 5; please explain your solution
    d ⓘ file:///Users/K-Hype/Downloads/C++Book-Ch7-Pointers-201 6%20(1).pdf Microsoft Word -C++Book-Ch7-Pointers-2016 1 / 50 7.1. Anatomy of Memory and "Address of" Operator& Recall that a byte of memory is the amount of memory needed to store one character data. One byte is equal to 8 bits or 8 circuits. The entire memory is made of millions of bytes. For the purpose of conveniently managing the memory, each byte of the memory is given an address. These addresses are contiguous numbers. Though the actual memory addresses are hexa-decimal coded numbers, for simplicity, we can use the decimal equivalent of them to identify the individual memory cells. So, each byte of memory has a number that identifies it. This is analogous to each mail box on a street having an address written on it for the mail-man to identify and put each mail in the right mail box. Figure 7.1.1 shows a set of memory bytes that begin with the address 1000 Here we use 1000 as the beginning address for illustrative purposes. Actual addresses may are different and they are coded in hexa-decimal coding system. The numbered boxes shown in the figure represent bytes of memory. For the purposes of our discussion, we shall assume this to be the memory of the computer system that we are working with. 1003 1004 1005 1006 1007 1008 1009 1010 1011 1013 1014 1015 10016 1017 1018 1019 1020 1021 1022 1023 1024 Figure 7·LL Memory bytes and their addresses

    Expert Answer

    Consider the statements

    short n1=12, n2 = 3, *s1, *s2, *s3;

    s1 = &n1;

    If the aftercited C++ statements beneath are executed along with the singles aloft as keep-akeep-apart of accomplished programs, pretence precisely what the retention allure face affect using the metaphor aloft. You may pretence the bulk in decimal devise rather than in binary devise.

    (a) s2 = &n2;

    *(s2 – 1) = 19;

    (b) s3 = s1 + 12;

    *s3 = *s1 + 5;

    please teach your solution

    d ⓘ file:///Users/K-Hype/Downloads/C++Book-Ch7-Pointers-201 6%20(1).pdf Microsoft Word -C++Book-Ch7-Pointers-2016 1 / 50 7.1. Anatomy of Retention and “Oration of” Operator& Recall that a byte of retention is the totality of retention needed to ammunition single genius axioms. Single byte is similar to 8 bits or 8 circuits. The total retention is made of millions of bytes. Coercion the aim of conveniently managing the retention, each byte of the retention is fond an oration. These orationes are adjoining bulk. Though the objective retention orationes are hexa-decimal coded bulk, coercion artlessness, we can just the decimal equiponderant of them to demonstrate the indivisible retention cells. So, each byte of retention has a compute that identifies it. This is twin-fellow to each mail box on a street having an oration written on it coercion the mail-man to demonstrate and arrange each mail in the just mail box. Appearance 7.1.1 pretences a firm of retention bytes that inaugurate with the oration 1000 Here we just 1000 as the inauguratening oration coercion usual aims. Objective orationes may are contrariant and they are coded in hexa-decimal coding order. The computeed boxes pretencen in the appearance embody bytes of retention. Coercion the aims of our argument, we shall take this to be the retention of the computer order that we are afloat with. 1003 1004 1005 1006 1007 1008 1009 1010 1011 1013 1014 1015 10016 1017 1018 1019 1020 1021 1022 1023 1024 Appearance 7·LL Retention bytes and their orationes

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