Homework Solution: Complete the calculations using the correct number of significant figures. In…

    INTRODUCTION TO CHEMISTRY LAB POSTLAB D Complete the calcalstions using the coe umer of sgneficant fes In msluple seqp ealcula, track gicas figures out do not eound until the end . An Mass umb sre m the E 143200 + 5.330 43 33 너 29102-90 5916 284o 105006-454510 gol13122 00 % 233m 43.95 100/1.510 3. Complete the cakculation for percent daffierence shesing the corec.oumber of siunafican fipanc in the Round only the final answer. Step 1: Solve the equation in the numerstor Apply Significant Figures rules for addition and sobtraction Dont round yet 110.009-9974 1 gl 10.00g o, a = 10.00 9 Step 2: Complete the division problem. Apply Significant Figures rules for nmulteplication and dirvsion Do not round yet Step 3: Finally, malmply by 100% (an exact number) and round the answer to the correct number of sgufont figures x 100% Solve 2 and 3 asap
    Complete the calculations using the correct number of significant figures. In multiple calculations, track significant figures but do not round until the end. Round in 3 decimal places 4.11983 _____ How many significant figures ________ Complete the following computations using significant figures rules. Complete this calculation for percent difference showing the correct number of significant figures in the non-rounded values by placing a line over the last certain digit. Round only the final answer. Step 1: Solve the equation in the numerator. Apply Significant Figures rules for addition and subtraction. Don't round yet [10.00g - 9.9741 g]/10.00g = /10.00 g Step 2: Complete the division problem. Apply Significant Figures rules for multiplication and division. Do not round yet Step 3: Finally, multiply by 100% (an exact number) and round the answer to the correct number of significant figures. _____ times 100 % = __________ %

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    Answer:

    INTRODUCTION TO CHEMISTRY LAB POSTLAB D Complete the calcalstions using the coe umer of sgneficant fes In msluple seqp ealcula, way gicas figures quenched do referable eound until the purpose . An Mass umb sre m the E 143200 + 5.330 43 33 너 29102-90 5916 284o 105006-454510 gol13122 00 % 233m 43.95 100/1.510 3. Complete the cakculation coercion percent daffierence shesing the corec.oumber of siunafican fipanc in the Circular simply the ultimate exculpation. Step 1: Solve the equation in the numerstor Apply Momentous Figures rules coercion analysis and sobtraction Dont circular referablewithstanding 110.009-9974 1 gl 10.00g o, a = 10.00 9 Step 2: Complete the resistance collection. Apply Momentous Figures rules coercion nmulteplication and dirvsion Do referable circular referablewithstanding Step 3: Ultimately, malmply by 100% (an rectify estimate) and circular the exculpation to the rectify estimate of sgufont figures x 100% Solve 2 and 3 asap

    Complete the cautions using the rectify estimate of momentous figures. In multiple cautions, way momentous figures except do referable circular until the purpose. Circular in 3 decimal places 4.11983 _____ How manifold momentous figures ________ Complete the aftercited computations using momentous figures rules. Complete this caution coercion percent discord showing the rectify estimate of momentous figures in the non-rounded values by placing a sequence aggravate the decisive sure digit. Circular simply the ultimate exculpation. Step 1: Solve the equation in the numerator. Apply Momentous Figures rules coercion analysis and disjunction. Don’t circular referablewithstanding [10.00g – 9.9741 g]/10.00g = /10.00 g Step 2: Complete the resistance collection. Apply Momentous Figures rules coercion reproduction and resistance. Do referable circular referablewithstanding Step 3: Ultimately, dilate by 100% (an rectify estimate) and circular the exculpation to the rectify estimate of momentous figures. _____ times 100 % = __________ %

    Expert Exculpation

    Answer:

    Step 1 :

    10.00 g- 9.9741 g/ 10.00g = 0.0259 g/ 10.00 g

    Step 2:

    0.0259 g/ 10.00 g = 0.00259 g

    Step 3:

    0.00259g X 100% = 0.259