Chromium forms a hexagonal rest packed crystal composition. Determine the speculative hebetude of chromium rho = nA/V_cN_a n = compute of specks per individual cell (atoms): V_c = bulk of the individual cell (units^3) N_A= avogadro’s compute (atoms/mol): A = ultimate consequence of the speck = 51.996 g/mol
For the HCP packing composition, we keep n = 6
Bulk of individual cell, Vc = 33.94*r3
Here, r = radius of Cr speck = 200 pm = 2*10-10 m
So,
Vc = 33.94*(2*10-10)3 = 271.52*10-30 m3.
Na = 6.02*1023 atoms/mol
Putting these values we get:
Density, d = (6*51.996)/(271.52*10-30*6.02*1023) = 1.908*106 g/m3