Homework Solution: C++ Programming Help Please! I have asked this same question man…

    C++ Programming Help Please! I have asked this same question many times on Chegg... never got a good answer NOTE: READ ENTIRE PROGRAM DESCRIPTION CAREFULLY! Thank You! Program Info: Write a program that accepts a year written as a four-digit Arabic (ordinary) numeral and outputs the year written in Roman numerals. Important Roman numerals are V for 5, X for 10, L for 50, C for 100, D for 500, and M for 1,000. Recall that some numbers are formed by using a kind of subtraction of one Roman “digit”; for example, IV is 4 produced as V minus I, XL is 40, CM is 900, and so on. A few sample years: MCM is 1900, MCML is 1950, MCMLX is 1960, MCMXL is 1940, MCMLXXXIX is 1989. Assume the year is between 1000 and 3000. Your program should include a loop that lets the user repeat this calculation until the user says she or he is done. More Important Info/OUTPUT: Enter an Arabic number: 2456 2456 is MMCDLVI in Roman numerals Play again? Y Enter an Arabic number: 1359 1359 is MCCCLIX in Roman numerals Play again? N Read the number as an integer: e.g. 9786 Use arithmetics to separate each digit into separate ints: (do you know what the modulus operator is? “%” No? look it up.) USE THE MODULUS OPERATOR -> % ones will be 6 tens will be 8 hundreds will be 7 thousands will be 9 ***use FOUR SWITCH CASES to output the correct string for each digit: cout<<”XX” in case of tens being 2 cout<<”XXX” in case of tens being 3 etc. ***As with all the projects in this chapter, wrap this whole thing in a “Play another game” loop to allow the user to play as many times as they like. MAKE SURE TO USE FOUR SWITCH CASES FOR OUTPUT!!! Please Note: Keep the program simple... use simple commands DO NOT use .append ^^^ READ PROGRAM DESCRIPTION CAREFULLY PLEASE ^^^ (I have asked this question several times on Chegg... and never got a proper answer.. please help me...)

    Expert Answer

    • #include<iostream> using namespace std;

    C++ Programming Aid Content! I keep asked this similar interrogation manifold times on Chegg… never got a amiable vindication

    NOTE: READ ENTIRE PROGRAM DESCRIPTION CAREFULLY! Thank You!

    Program Info: Write a program that accepts a year written as a four-digit Arabic (ordinary) numeral and outputs the year written in Roman numerals. Important Roman numerals are V restraint 5, X restraint 10, L restraint 50, C restraint 100, D restraint 500, and M restraint 1,000. Reccomplete that some quantity are restraintmed by using a skin of disconnection of undivided Roman “digit”; restraint copy, IV is 4 produced as V minus I, XL is 40, CM is 900, and so on. A scant illustration years: MCM is 1900, MCML is 1950, MCMLX is 1960, MCMXL is 1940, MCMLXXXIX is 1989. Assume the year is between 1000 and 3000. Your program should embrace a loop that lets the portraiturer cite this caution until the portraiturer says she or he is produced.

    More Important Info/OUTPUT:

    Enter an Arabic number: 2456

    2456 is MMCDLVI in Roman numerals

    Dramatize anew? Y

    Enter an Arabic number: 1359

    1359 is MCCCLIX in Roman numerals

    Dramatize anew? N

    Read the number as an integer: e.g. 9786

    Portraiture arithmetics to unconnected each digit into unconnected ints: (do you apprehend what the modulus operator is? “%” No? contemplate it up.)

    USE THE MODULUS OPERATOR -> %

    ones accomplish be 6

    tens accomplish be 8

    hundreds accomplish be 7

    thousands accomplish be 9

    ***portraiture FOUR SWITCH CASES to output the chasten string restraint each digit:

    cout<<”XX” in contingency of tens life 2

    cout<<”XXX” in contingency of tens life 3

    etc.

    ***As with complete the projects in this condition, cover this integral man in a “Dramatize another game” loop to completeow the portraiturer to dramatize as manifold times as they enjoy.

    MAKE SURE TO USE FOUR SWITCH CASES FOR OUTPUT!!!

    Content Note: Keep the program mere… portraiture mere commands DO NOT portraiture .append

    ^^^ READ PROGRAM DESCRIPTION CAREFULLY PLEASE ^^^

    (I keep asked this interrogation diverse times on Chegg… and never got a special vindication.. content aid me…)

    Expert Vindication

    • #include<iostream>

      using namespace std;

      int main()

      {

      int n;

      char ch = ‘ ‘;

      do{

      cout << “nEnter an Arabic number: “;

      while(cin>>n)

      {

      int x,y,k,l;

      l=(n/1000)*1000;

      if(l==1000)

      cout<<“M”;

      if(l==2000)

      cout<<“MM”;

      if(l==3000)

      cout<<“MMM”;

      if(l==4000)

      cout<<“-IV”;

      if(l==5000)

      cout<<“-V”;

      if(l==6000)

      cout<<“-VI”;

      if(l==7000)

      cout<<“-VII”;

      if(l==8000)

      cout<<“-VIII”;

      if(l==9000)

      cout<<“-IX”;

      if(l==10000)

      cout<<“-X”;

      k=(n%1000);

      k=(k/100)*100;

      if (k == 100)

      cout<<“C”;

      else if (k == 200)

      cout<<“CC”;

      else if (k == 300)

      cout<<“CCC”;

      else if (k == 400)

      cout<<“CD”;

      else if (k ==500)

      cout<<“D”;

      else if (k == 600)

      cout<<“DC”;

      else if (k == 700)

      cout<<“DCC”;

      else if (k ==800)

      cout<<“DCCC”;

      else if (k == 900)

      cout<<“CM”;

      k=n%1000;

      l=k%100;

      y=(l/10)*10;

      if (y == 10)

      cout<<“X”;

      else if (y == 20)

      cout<<“XX”;

      else if (y == 30)

      cout<<“XXX”;

      else if (y == 40)

      cout<<“XL”;

      else if (y ==50)

      cout<<“L”;

      else if (y == 60)

      cout<<“LX”;

      else if (y == 70)

      cout<<“LXX”;

      else if (y ==80)

      cout<<“LXXX”;

      else if (y == 90)

      cout<<“XC”;

      x=l%10;

      if (x == 1)

      cout<<“I”;

      else if (x == 2)

      cout<<“II”;

      else if (x == 3)

      cout<<“III”;

      else if (x == 4)

      cout<<“IV”;

      else if (x ==5)

      cout<<“V”;

      else if (x == 6)

      cout<<“VI”;

      else if (x == 7)

      cout<<“VII”;

      else if (x ==8)

      cout<<“VIII”;

      else if (x == 9)

      cout<<“IX”;

      cout<<” in Roman numerals”;

      cout<<endl;

      cout <<“nDramatize anew?(Y/N): “;

      cin >> ch;

      ch = toupper(ch);

      }

      }while(ch==’Y’);

       

      return 0;

      }