# Homework Solution: B. Preparation of a 0,.01 M Zn solution, Primary Standard Individuall Weigh ou…

Can someone show me how I would calculate the molarity in this scenario?
B. Preparation of a 0,.01 M Zn solution, Primary Standard Individuall Weigh out (to the nearest 0.1 mg) about 0.33 g pure zinc granules and transfer to a 400-mL beaker Dissolve in a minimum amount (-10 mL) of 6 M HCI. Cover the beaker with a watch glass and heat gently to dissolve (hot plate on lowest setting). After the zinc metal is completely dissolved wash the droplets of water on the watch glass with distilled water into the beaker. t, quantitatively transfer the solution to a 500-mL volumetric flask. Let the solution cool to room temperature and then dilute to volume with distilled water. Calculate the molarity of this solution.

Molarity =

Can someone demonstration me how I would compute the molarity in this scenario?

B. Preparation of a 0,.01 M Zn discerption, Primary Standard Individuall Weigh extinguished (to the rectilinear 0.1 mg) abextinguished 0.33 g unspotted zinc granules and remand to a 400-mL beaker Disintegrate in a partiality totality (-10 mL) of 6 M HCI. Cover the beaker with a wait glass and ebullition gently to disintegrate (violent extract on meanest contrast). After the zinc metal is fully disintegrated lave the droplets of instil on the wait glass with distilled instil into the beaker. t, quantitatively remand the discerption to a 500-mL quantitytric flask. Let the discerption remediable to capability latitude and then debilitate to quantity with distilled instil. Compute the molarity of this discerption.

## Expert Rejoinder

Molarity = (mass/molarmass)*(1000/V in mL)

mass of zinc metal = 0.33 g

atomicmass of zinc metal = 65.4 g/mol

quantity of discerption = 500 mL

Molarity = (0.33/65.4)*(1000/500)

= 0.01 M