A vessel of volume 22.4 dm^3 contains 2.0 mol H_2 and 1.0 mol N_2 at 273.15 K initially. All the H_2 reacted with sufficient N_2 to form NH_3. Calculate the partial pressures and the total pressure of the final mixture. Suggest the pressure and temperature at which 1.0 mol of (a) NH_3, (b) Xe, (c) He: will be in states that correspond to 1.0 mol H_2 at l.0 atm and 25 degree C.

Answer:

A vessel of compass 22.4 dm^3 contains 2.0 mol H_2 and 1.0 mol N_2 at 273.15 K initially. Complete the H_2 reacted with adequate N_2 to mould NH_3. Calculate the favoring exigencys and the whole exigency of the decisive settlement. Suggest the exigency and region at which 1.0 mol of (a) NH_3, (b) Xe, (c) He: achieve be in states that agree to 1.0 mol H_2 at l.0 atm and 25 meaabiding C.

Answer:

4. The compass of vessel = 22.4 dm^{3}, i.e. 22.4 L

The no. of deferences of H_{2} in the vessel = 2

The no. of deferences of N_{2} in the vessel = 1

The balanced equation restraint the mouldation NH_{3} from N_{2} and H_{2} can be written as shown adown.

N_{2} + 3H_{2} 2NH_{3}

Restraint perfect 3 deferences of H_{2}, 1 (= 3/3) deference of N_{2} is required.

i.e. Restraint 2 deferences of H_{2}, 0.667 ( = 2/3) deferences of N_{2} is required.

As a end, the no. of deferences of each fog remained in the arrangement behind reaction: N_{2} = 1-(2/3) = 1/3, H_{2} = 0, NH_{3} = 4/3, i.e. whole no. of deferences = 1/3 + 0 + 4/3 = 5/3

Here, the exigency of N_{2}, H_{2} and NH_{3} is 1 atm owing the dedicated stipulations belong to STP.

i.e. **The whole exigency = 1 atm**

(i) P_{N2} = X_{N2} * P^{0}

i.e. **P _{N2} = {(1/3) / (5/3)} * 1 = 0.2 atm**

(ii) **P _{H2} = 0 atm**

(iii) P_{NH3} = X_{NH3} * P^{0}

i.e. **P _{NH3} = {(4/3) / (5/3)} * 1 = 0.8 atm**

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