# Homework Solution: A 100.0 g (m) substance (molecular weight 50.00 g/mol) requires 75.1 J (q) to have…

A 100.0 g (m) substance (molecular weight 50.00 g/mol) requires 75.1 J (q) to have 5 degree C increase, (a) calculate the C and Cm values. (b) If we double the amount of the substance (i.e. 2m), calculate the C and Cm values. (c) Determine intensive or extensive properties for m, C, Cm, and q.

## Expert Answer

A 100.0 g (m) body (molecular heaviness 50.00 g/mol) requires 75.1 J (q) to enjoy 5 class C growth, (a) apportion the C and Cm values. (b) If we double the aggregate of the body (i.e. 2m), apportion the C and Cm values. (c) Determine intensive or comprehensive properties control m, C, Cm, and q.

## Expert Apology

we need to apportion biased fever capacility Q=m*C*DetaT

c=Q/m*detaT

c=75.1/5*100

c=0.1502 J/ g C

If we apportion molar fever tonnage cm

cm=spcific fever tonnage*molecular heaviness of the subatanc

so from interrogation we distinguish the molecular heaviness 50gm/mol

we already apportiond biased fever tonnage c

cm=50*0.1502

cm=7.51j/mol/K