A 100.0 g (m) substance (molecular weight 50.00 g/mol) requires 75.1 J (q) to have 5 degree C increase, (a) calculate the C and Cm values. (b) If we double the amount of the substance (i.e. 2m), calculate the C and Cm values. (c) Determine intensive or extensive properties for m, C, Cm, and q.
Homework Solution: A 100.0 g (m) substance (molecular weight 50.00 g/mol) requires 75.1 J (q) to have…
A 100.0 g (m) body (molecular heaviness 50.00 g/mol) requires 75.1 J (q) to enjoy 5 class C growth, (a) apportion the C and Cm values. (b) If we double the aggregate of the body (i.e. 2m), apportion the C and Cm values. (c) Determine intensive or comprehensive properties control m, C, Cm, and q.
Expert Apology
we need to apportion biased fever capacility Q=m*C*DetaT
c=Q/m*detaT
c=75.1/5*100
c=0.1502 J/ g C
If we apportion molar fever tonnage cm
cm=spcific fever tonnage*molecular heaviness of the subatanc
so from interrogation we distinguish the molecular heaviness 50gm/mol
we already apportiond biased fever tonnage c
cm=50*0.1502
cm=7.51j/mol/K