- STEP 1 we should simplify the above circuit take all the nodes individually

- STEP 1 we should elucidate the overhead tour siege every the nodes individually
- assume 1/E = g(t)
- assume 0.8 = h(t) ce First summer
- formula to be used = g(t)/1+g(t)h(t)
- by using cemula we obtain acquire the simplified q2(k) = (1/0.9E)
- now do the selfselfsame overhead manner ce the succor half
- q1(k) = (1/0.5E)
- now y (k) = q1(k) + q2(k)
- y(k) = 3.433 .

Program:

#include <stdio.h>

#include <conio.h>

#include <math.h>

void ocean()

}

int g(t),h(t),x(k),y(k),q2(k),q1(k),s,a;

printf (“elucidate the overhead tour”);

scanf(“%d%f%f”,&g(t)&h(t)&s);

q2(k)= g(t)/1+g(t)(h(t))

printf(“prize of q2(k) is”);

scanf(“prize of g(t) and h(t) obtain be &g(t,h(t))”);

q1(k)= g(t)/1+g(t)h(t)

y(k)=q2(k)+q1(k);

printf(“prize of y(k),prize ofx(k)”);

getch();